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------=_NextPart_000_0046_01C9442A.C1555500 Content-Type: multipart/alternative; boundary="----=_NextPart_001_004D_01C9442A.C15A3700" ------=_NextPart_001_004D_01C9442A.C15A3700 Content-Type: text/html; charset="Windows-1252" Content-Transfer-Encoding: quoted-printable Content-Location: http://www.elhuevodechocolate.com/mates/mates7.htm El huevo de chocolate_Matem=E1ticas para = ni=F1os =

El huevo = de=20 chocolate
El "huev" m=E1s=20 "guachi"

Est=E1s en = > El huevo de=20 chocolate > Matem=E1ticas = para=20 ni=F1os > Operaciones = divertidas

MATEM=C1TICAS PARA=20 NI=D1OS

OPERACIONES=20 DIVERTIDAS

LOS = OCHO=20 OCHOS

Utilizando = =FAnicamente ocho=20 ochos y las operaciones matem=E1ticas b=E1sicas (suma, resta, = multiplicaci=F3n y=20 divisi=F3n) conseguir el n=FAmero 1000

Soluci=F3n:
888 + 88 + 8 + 8 + 8 =3D=20 1.000

LOS = CUATRO=20 DOSES

Utilizando cuatro 2 = y las=20 operaciones matem=E1ticas b=E1sicas (suma, resta, multiplicaci=F3n = y divisi=F3n)=20 conseguir los n=FAmeros del 1 al 10. Pueden combinarse dos 2 para = formar el=20 n=FAmero 22.
 

SOLUCI=D3N

1 (2 + 2 - 2) / = 2 =3D (2 - 2)=20 + (2 / 2) =3D 22 / 22 =3D (2 x 2) / (2 x 2) =3D (2 x 2 - 2) / = 2
2 (2 / 2) + (2 / 2) =3D = 2 + [(2 -=20 2) / 2]
3 (2 + 2 + 2) / 2 =3D 2 = + 2 - (2 /=20 2) =3D [2 - (2 / 2)] + 2
4 2 + 2 + 2 - 2 =3D (2 = x 2) + 2 - 2=20 =3D 2 + [(2 + 2) / 2] =3D (2 + 2) x (2 / 2)
5 2 + 2 + (2 / 2) =3D = (2 x 2) + (2=20 / 2)
6 (2 x 2 x 2) - = 2
7 --
8 2 + 2 + 2 + 2 =3D (2 = x 2) + 2 +=20 2
9 (22 / 2) - = 2  =20
10 (2 x 2 x 2) + 2 =3D = (22 - 2) /=20 2
11 --
12 (22 + 2) / = 2
13 (22 / 2) + = 2
14 --
15 --
16 2 x 2 x 2 x=20 2

LOS = CUATRO=20 TRESES

Utilizando cuatro 3 = y las=20 operaciones matem=E1ticas b=E1sicas (suma, resta, multiplicaci=F3n = y divisi=F3n)=20 conseguir los n=FAmeros del 1 al 10. Pueden combinarse dos 3 para = formar el=20 n=FAmero 33.
 

SOLUCI=D3N

1 (3 - 3) + (3 / 3) =3D = 33 /=20 33
2 (3 / 3) + (3 / = 3)
3 (3 + 3 + 3) / 3 =3D = (3 x 3) - (3=20 + 3)
4 (3 x 3 + 3) / = 3
5 3 + [(3 + 3) / = 3]
6 3 + 3 + 3 - 3 =3D (3 = / 3) x (3 +=20 3)
7 (3 + 3) + (3 / = 3)
8 (33 / 3 ) - = 3
9 (3 x 3) x (3 / 3) =3D = (3 x 3 x 3)=20 / 3
10 (3 x 3) + (3 / = 3)
11 --
12 3 + 3 + 3 + = 3
13 --
14 (33 / 3 ) + = 3
15 (3 x 3) + (3 +=20 3)

LOS = CUATRO=20 CUATROS

Utilizando cuatro 4 = y las=20 operaciones matem=E1ticas b=E1sicas (suma, resta, multiplicaci=F3n = y divisi=F3n)=20 conseguir los n=FAmeros del 1 al 10. Pueden combinarse dos 4 para = formar el=20 n=FAmero 44.
 

SOLUCI=D3N

1 (4 + 4) /  (4 + = 4) =3D (4 x=20 4) / (4 x 4) =3D 4 - 4 + (4 / 4) =3D (4 + 4 - 4) / = 4 
2 (4 / 4) + (4 / = 4)
3 (4 + 4 + 4) / 4 =3D = (4 x 4 - 4) /=20 4
4 4 + [( 4 - 4) / = 4]
5 (4 x 4 + 4) / = 4
6 4 + [(4 + 4) / = 4]
7 4 + 4 - (4 / = 4)
8 (4 + 4) x (4 / 4) =3D = (4 x 4) - 4=20 - 4
9 4 + 4 + (4 / = 4)
10 (44 - 4) / = 4
11 --
12 [4 - (4 / 4)] x 4 =3D = (44 + 4) /=20 4 
13 --
14 --
15 4 x 4 - (4 / 4) =3D = (44 / 4) +=20 4
16 4 + 4 + 4 + 4 =3D (4 = x 4) + 4 -=20 4
17 (4 x 4) +  (4 /=20 4)

LOS = CUATRO=20 CINCOS

Utilizando cuatro 5 = y las=20 operaciones matem=E1ticas b=E1sicas (suma, resta, multiplicaci=F3n = y divisi=F3n)=20 conseguir los n=FAmeros del 1 al 10. Pueden combinarse dos 5 para = formar el=20 n=FAmero 55.
 

SOLUCI=D3N

1 (5 + 5 - 5) / = 5 =3D (5 - 5)=20 + (5 / 5) =3D 55 / 55 =3D (5 x 5) / (5 x 5)
2 (5 / 5) + (5 / = 5)
3 (5 + 5 + 5) / = 5
4 (5 x 5 - 5) / = 5
5 5 + [(5 - 5) / = 5]
6 (5 x 5 + 5) / 5 =3D = (55 / 5) - 5=20
7 5 + [(5 + 5) / = 5]
8 --
9 5 + 5 - (5 / 5) =3D = [5 - (5 / 5)]=20 + 5
10 5 + 5 + 5 - 5 =3D (5 = + 5) x (5 /=20 5) =3D (55 - 5) / 5 =3D (5 x 5) - (5 + 5)
11 5 + 5 + (5 / = 5)
12 (55 + 5) / = 5 
13 --
14 --
15 (5 x 5) - 5 - = 5
16 (55 / 5) +=20 5

DEL = UNO AL=20 CUATRO

(Rafael Cerezo, = Salamanca,=20 Espa=F1a)

Utilizando los = cuatro primeros=20 n=FAmeros (1, 2, 3 y 4)  y las operaciones matem=E1ticas = b=E1sicas (suma,=20 resta, multiplicaci=F3n y divisi=F3n) conseguir los n=FAmeros del = 1 al 16.=20 Pueden combinarse dos n=FAmeros para formar otro n=FAmero=20 mayor.

SOLUCI=D3N

1 (1 x = 2) + 3 -=20 4 9 (4 + 3 = + 2) x=20 1
2 (1 + 2 = + 3) -=20 4 10 4 + 3 = + 2 +=20 1
3 (4 - 2 = - 1) x=20 3 11 (3 x = 4) + 1 -=20 2
4 (4 + 2 = + 1) -=20 3 12 (2 - = 1) x 4 x=20 3
5 12 - 4 = -=20 3 13 (3 x = 4) + 2 -=20 1
6 (3 x = 4) / ( 2 x=20 1) 14 (1 x = 2) + (3 x=20 4)
7 (24 / = 3) -=20 1 15 (3 + = 2) x (4 -=20 1)
8 (4 + 3 = + 2) -=20 1 16 (3 + 2 = - 1) x=20 4

CALCULAR=20 6

Conseguir el n=FAmero 6 = utilizando tres=20 unos, tres doses, tres treses, tres cuatros y as=ED sucesivamente hasta = tres=20 nueves con las operaciones matem=E1ticas b=E1sicas (suma, resta, = multiplicaci=F3n y=20 divisi=F3n), ra=EDz cuadrada y factorial.=20

SOLUCI=D3N

(1 + 1 = + 1) ! =3D=20 6
2 + 2 = + 2 =3D=20 6
(3 x = 3) - 3 =3D=20 6
√4 + √4 + √4 =3D=20 6
5 + (5 = / 5) =3D=20 6
6 - 6 = + 6 =3D=20 6
7 - (7 = / 7) =3D=20 6
8 - = (√√8 + 8) =3D=20 6
(9 + = 9) / √9 =3D=20 6
=A9 El = huevo de=20 chocolate=20
M=E1s = Matem=E1ticas para=20 ni=F1os
Volver a la = p=E1gina=20 principal
El huevo de=20 chocolate
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